The physics of huge urban drops to flat?

no.

F=MA

when you bend your knees more you are absorbing less force over a longer period of time, than if you had your knees locked. The more your legs bend(assuming you dont just compress all the way down knees to face status), the less the deceleration is, and the max force is less.

what i think you mean to say is the the amount of work your legs do is constant regardless of how you land.

You arent showing much of a physics background either...

 
i read what you posted.

wrong

i did not repeat what you said

contact time is not the same if you bend your legs. contact time is the time it takes to change from your initial velocity to 0, so if your legs are locked, the contact time will be very short, and if you bend them, it will be longer

F=m*delta v/delta t

since m and delta v are constant (delta v is going to be from some number to zero , no matter if you break your legs or not), force is inversely proportional to delta t, and so if delta t increases, F decreases. This means that when you extend the contact time by bending your legs, the maximum force that is exerted on your legs decreases.

think of it like this...

throw an egg at drywall. the egg breaks because the contact time is almost instantaneous, causing the force to be quite large.

throw the same egg at a bedsheet held up by two people. the egg doesn't break, no matter how hard you throw it, because the contact time between the egg and the sheet is significantly larger, and this causes the force exerted on the egg to be very small.

if you have ever played lacrosse or even hockey you would "cradle" or "cusion" the ball/puck when you catch it with your stick, so that it doesnt bounce off. same idea here

 
this thread would be a lot less dildos if the first poster just told him to build a cheese wedge landing
 
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