The OFFICIAL help me with my chemistry thread

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Ok, here's the problem (and I might post more later on)...

Determine the frequency of light with a wavelength of 0.000047 cm.

Any help will be appreciated.
 
yea its hard to leave ns and do your homework in a place thats quiet, ive found myself slacking in school way too much because of ns, seriously
 
V=c/W

V is frequency

c is the speed of light

W is the wavelength

remember to convert the wavelength to nanometers to give a final unit of hertz.
 
i can't believe ima do this...

speed of light is 3 x 10*8 m/s

wavelength is .00000047m

devide .00000047 by 300000000 and you get your answer

its physics btw
 
im taking intro to chemistry and god its hard, or im stupid. probably both. i can only imagine what chemistry honors or AP could be like
 
Ok here's another one, ahem.

How are frequency and wavelength related in electromagnetic radiation?

and heres another...

Two compounds have the same empirical formula, must they have the same molecular formula? give an example.
 
i am taking chemistry i hate it but my brother is majoring in chemistry and biology in college so he helps me its awesome its like my own tutor
 
haha, yeah. I took AP and had the worst teacher. She literaly just told us to read the book and take notes, and never actualy explained anything. Not to mention i had no idea what half the AP test was about.
 
Hey vic I think it's safe to take out that 'Ban Skiatgore69' petition from your sig.
 
frequency and wavelength are inversely proportional to each other. the smaller the wavelength, the greater the frequency.

c=v*lambda, so divide c (which is 3 * 10^8 m/s by your wavelength (in meters), so that your units will end up to be 1/s, which is the same as a Hz (Hertz). i believe your unit was in cm, so divide it by 100 to get it into meters)

molecular formula and empirical formula dont have to be the same. empirical formula just gives the ratio of your elements, not the actual proportions. that is the molecular formula. for example, for empirical formula C3 H6 O3, the molecular formula can be that of pyruvate where its the same, or that of glucose C6 H12 O6.

and to the guy that said that this is physics, radiation can be treated from both a chemical and physical point of view.
 
remeber OIL RIG (oxidation is loss of electrons, Reduction is gain of electrons) the rest is just adding water and acid/base
 
Heres another,

What mass of silver will be produced when 65 g of copper reacts with an excess of silver nitrate? (507.6g)

and

How do you distinguish between an ionic, polar covalent and nonpolar covalent bond (pretty sure it has to do with electronegativity)
 
This is retarded. Dont you have a class discussion board dedicated for this? And us giving you the answers wont help you when it comes to a test. Take my advice, just sit down and learn how to do it. It'll benefit you in the long run.
 
When I'm trying to finish the problems I have no clue how to do, when it's due tomorrow, I don't have time to re-learn it. This packet counts as 50% of our final exam so as long as I finish this I can get a 40% on the actual test (which is multiple choice) and have a passing grade. I'm mostly done now, thanks to everybody that helped.
 
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