So, who like trig?

FUCK it disappeared

solve the following equation for all exact solutions of the domain {0,2pi}

3cos(squared)t = sin(squared)t

word.
 
You have to use your identities.

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You use the first one, and make that sin squared into a cos or vis versa whatever you want to do and then solve from there.
 
awwwwww shit.

well you would use:

sin^2 + cos^2 = 1

so say you want to make that sin squared into cosine it would be:

sin^2=1-cos^2
 
Explanation

3cos^2(t) = sin^2 (t)

Identity: sin^2= 1-cos^2

3cos^2(t) = 1-cos^2(t)

3cos^2(t)+cos^2(t)=1

4cos^2 = 1

cos^2 = 1/4

so cos =1/2 and therefore 60 degree angles in quadrant I and IV

I don't know if this is right, it has been over a year since I took this class.

 
ok, well

3cos(2)t=1-cos(2)t

4cos(2)t=1

cos(2)t=1/4

cost=+/-1/2

reference angle = 60

t= pie/3, 2pie/3, 4pie/3, 5pie/3

i think i litterally just did that question for homework
 
you guys didnt solve it correctly

when you go from cos^2t=1/4 and square root it, you get +/-1/2 which is HUGE. dont miss it
 
no no, fuck geometry proofs. worst time of my life. i have a 4.0 in math, i got a 1.5 when we did geometry proofs...
 
Mehh I am in statistics mode where everything I think of is in terms of probability.

SO glad I got that AP exam over with today.
 
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