notSOnifty
Member
A series circuit contains three resistors, R1=370 ohms, R2=480 ohms, and R3= 279 ohms. They are connected to a potential difference of 55 volts. How much current will flow through R2?
Can anyone tell me how to solve that?
NEED PHYICS HELP!!
- Thread starter notSOnifty
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A series circuit contains three resistors, R1=370 ohms, R2=480 ohms, and R3= 279 ohms. They are connected to a potential difference of 55 volts. How much current will flow through R2?
Can anyone tell me how to solve that?
notSOnifty
Member
it says series
notSOnifty
Member
i need to know before midnight
clrumivier4life
Active member
Yeah dude.
Resisters in series can be added together to get an equivalent resistance. Then just use I=V/R to find the current of the series. Since current is constant in a series circuit, that answer is the current through resister 2.
Resisters in series can be added together to get an equivalent resistance. Then just use I=V/R to find the current of the series. Since current is constant in a series circuit, that answer is the current through resister 2.
ThaLetterM.
Active member
my brain just exploded.