Math wizzes help me

[kstanz]

http://www.wolframalpha.com/input/?i=simplify+%28square+root+x^3%29+divided+by+%28cube+root+x^4%29

the first input thing id what im trying to figure out, simplify (square root x^3) divided (cube root x^4). i know the answer obviously but i don't know how to work that out. if someone could explain it to me that would be AWESOME (grade 10 math so nothing too in depth)

 

[Loco-Deer-Slayer]

[(x^3)^1/2]/[(x^4)^1/3]
x^9/6/x^8/6
x^1/6
I think

 

[TOAST.]

[x^(3/2)]/[x^(4/3)]

[x^(9/6)]/[x^(8/6)]

(9/6)-(8/6)=1/6

x^(1/6)

 

[DopeDiecuts]

1/x^6 I believe.

 

[a_pla5tic_bag]

i'm so glad i never have to take another math class all through college. not that thats any help but...

 

[c4t_l0ver]

every grade 10 in bc tomorrow, getttt ruddddy math 10 provincial.

9 am.

 

[JakeAssBeatClap]

likewise... I love environmental science.

 

[ChrisBoy]

hi

 

[CassiusClay]

sqrt x^3/crx^4

(x^(2/3))/(x^(3/4))

(x^(2/3))*(x^(-3/4))

x^(-6/12)

x^(-1/2)

1/2x

/ans

 

[CassiusClay]

or type this into wolfram....(sqrtx^3)/(cuberootx^4)... and realize I blew it.

 

[kstanz]

thanks for the help guys but still doesn't really show me how to figure it out, i kNOW the answer is root 6 x. Guess i will just try and go in early tmrrw before my test, +K

 

[eldridge]

i like rolling papers and black and yellow.

wait what?

 

[DopeDiecuts]

Wrong. Say x=1.

LS=[sr(1)^3]/[cr(1)^4]

LS=[sr(1)]/[cr(1)]

LS=1

With your answer:

RS=(1/2)(1)

RS=1/2

Thus LS does not = RS.

With the correct answer:

RS=1/(1)^6

RS=1

Therefore LS = RS.

 

[DopeDiecuts]

Oops my bad.

 

[.AR6rider.]

I haven't taken math in 5 years and it's great. The sad thing is, I used to be really good at math. Tested into calc 3 my freshman year of college. Fuck math.

 

[quixotic]

I have nothing to contribute to this thread besides to claim that I haven't taken math in 3 years and don't ever need to again.