Math riddle...

eithier 50^2 or 50 x 4 i don't have a calc near me....but im probably wrong seeing as this is a riddle
 
What are the dimensions of said space? The perimeter will change depending on the length of each side.
 
the shape of the area that you are trying to find the perimeter of? a square with an area of 50 sq miles has a perimeter of 28.28 miles while a circle with an area of 50 sq miles has a circumference(perimeter) of 25.07... unless i really screwed that up.
 
no calc on me, but i got about 28, since 50 is by 49, which is a perfect square and is 7, so each side is about 7, and 7 times 4 equals 28
 
it would take no miles!!!!! it would take 2 feet!!!! hahahah you cant fool me. i dont need any miles to walk anywhere. i just need my own 2 feet and a pair of shoes maybe
 
wait, you never specified if it was a perfect square of land, so it could be a rectangle that was 50 by 1, therefore the answer would be 102
 
this riddle sucks theres going to be some technicality that no one will understand cause you worded the question wrong.
 
Yes, it really does. We did this on day one of AP Calculus.

Whoever said it depends is correct. We don't know the shape, therefore it is impossible to know the perimeter. If its all squiggly and shit just use Reimann's Sums and you're close enough.
 
The most correct answer that I can give you is the perimeter is ≥ 17.366 meters.

This is because the least amount of perimeter that a shape can have with an area of 24 square meters is the perimeter of a circle with a like area. The perimeter of such a circle is about 17.366 meters.

A=πr²

24=πr²

r=(24/π)^½

P=2πr

P=2π(24/π)^½

P≈17.366

The greatest perimeter that a shape can have with an area of 24 square meters is infinite. Imagine a rectangle with an incredibly small width. In order for this rectangle to have an area of 24 square meters, the length would have to be incredibly long. this would make the perimeter of the rectangle roughly twice its length. If you make the width small enough the perimeter becomes infinite.
 
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