Math homework help
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Wallisch_pl
Active member
I just had to go find my algebraic calc, lol, and I don't understand your question,
chickenonabun
Member
So using the power rule you find the derivative (which is its own function that describes the slope of the first function at any giver point. The derivative is 4x. Then you put The x value you want to find the slope of in for the derivative, and you get f'(-2)=-8.
SlurmrnHurnyBurn
Member
if you can't figure out the slope of a line you're gonna have some troubles with the rest of life.
Theskiingguy
Member
it's a tangent line of an exponential equation/function... not a linear line, totally different bud.
But yeah, that guy a couple posts down is right. But if they're making you do the
f(x-a) - f(a)
--------------
f(a)
or whatever that equation is, then that's totally different. Let me know if thats what you're supposed to do and I can help. Just can't remember the exact equation
But yeah, that guy a couple posts down is right. But if they're making you do the
f(x-a) - f(a)
--------------
f(a)
or whatever that equation is, then that's totally different. Let me know if thats what you're supposed to do and I can help. Just can't remember the exact equation
Captain_Slow
Active member
I dont think he'll be using that method to find the answer... i learned that in precal but skipped it in calc (which im assuming hes taking now)
Theskiingguy
Member
We had to do it in our calc class in the beginning, but then we were able to use the "short cut" way, so idk
DaffyDaDak
Member
Bump so I dont have to make a new thread,
this projects due tomorrow and ive done math all day and im exhausted and cant get my mind to compute anymore can someone help me with this.
Write an equation (y = mx+b) for the graph of a linear function that:
has slope 5 and y-intercept -5
has slope -5/6 and y-intercept -6/5
has slope -5 and y-intercept 6
this projects due tomorrow and ive done math all day and im exhausted and cant get my mind to compute anymore can someone help me with this.
Write an equation (y = mx+b) for the graph of a linear function that:
has slope 5 and y-intercept -5
has slope -5/6 and y-intercept -6/5
has slope -5 and y-intercept 6
DaffyDaDak
Member
13575018:erikK said:
13575029:itzki said:
grade 11 actually haha.... i got another one for you guys
For the function f(x) = -3x + 8, determine f(-2).
DaffyDaDak
Member
13575154:DaffyDaDak said:
pretty sure its 2
AgitatedHiatus
Member
13575166:DaffyDaDak said:
It's not. Since f(x) means you put whatever number you have as "x" in the equation, -2 is taking the place of x in the equation. You take -3(-2) + 8 which gives you an answer of 14.
lucarichardson
Member
Step 1. Use power rule to find derivative of the function 2x^2:
Constant 2 times n (in x^n) times x^(n-1), or x^1, or x
fprime= 4x
Step 2. Plug in x value -2 to find the derivative at that point.
fprime(-2)=4(-2)
fprime(-2)= -8
Step 3. Pee in her butt
Step 4. Slope of the tangent line at (-2, 8)= fprime(-2)= -8
Step 5. Find tangent line using point slope form
y= -8(x+2)+8
Constant 2 times n (in x^n) times x^(n-1), or x^1, or x
fprime= 4x
Step 2. Plug in x value -2 to find the derivative at that point.
fprime(-2)=4(-2)
fprime(-2)= -8
Step 3. Pee in her butt
Step 4. Slope of the tangent line at (-2, 8)= fprime(-2)= -8
Step 5. Find tangent line using point slope form
y= -8(x+2)+8
