Answer:
You have Ax2+bx+c
Find two numbers (we'll say f and t) that when multiplied together equal the same thing as A times C, AND those original two numbers (f,t) have to equal b when added together.
Then:
replace bx with f and t (but still with the x part)
So you have:
Ax2+fx+tx+c
Then:
(Ax2+fx)+(tx+c)
Then:
Out of each of those parenthases you need to factor out a common number so both parenthasis look the same. Example: if you have (4x^2+2x)+(6x+3), you can take a 2x out of the first parenthases and a 3 out of the second, and then they will both be the same:
2x(2x+1)+3(2x+1).
Then:
Combine the terms outside the parenthasis and combine the two parenthases that are the same into one:
(2x+3)