How would you do this integral?

MSP

 
i figured it out...-2x-x^2 is the same as 1-1-(-2x-x^2) which can also be rewritten 1-(1-(-2x-x^2)) which factors to 1-(x+1)^2, and then when you take the integral of 1/(1-(x+1)^2) you get sin^-1(x+1)
 
don't think that was a burn bro. and if you had taken calc it should have been easy to figure that out.

but ya you got it right to the threadmaker. if you factor and rewrite its not to bad. you can also use a natural log but that doesn't make it much easier.
 
I didn't think double and triple integrals were all that hard. The hardest part was learning how to do simple integrals and then double and triples were just based off of those. Now differential equations...that's a tougher class.
 
Neither can I, but it's because it's been over a year since I've taken Calc 2. Being advanced in math does squat for you if nowhere in town offers higher than Calc 2.
 
i got fucking raped by my calc midterm a few weeks ago... 8/45. i'm taking calc at UBC with no calculus background from high school or college, so yeah, i'm getting owned.
 
put your roots to powers of -1/2 so you can move it to the top. It makes getting the antiderivative 10x easier. That one looks like a bitch tho. I dont even want to attempt.
 
This stuff isn't so incredible, so stop making it sound amazing that we can do calculus. Thread is useless now that we answered the question.
 
i'll probably only be here for 5 years, including co-op time, and i'll be something called a "geological engineer"....... the average salary of geological engineers in canada is about $122,500. seriously, i don't care how long it takes to do my degree, i fucking love it here, and i know that before i graduate i'll have a job lined up, and i'll probably be buying a damn nice car as a grad present for myself.
 
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