How much speed will a ramp this big give u?

garrett.

garrett.

Active member
its gunna be about 5' 6" tall, how mch speed do ut hink it will give u?and how big will u be able to go do u think?
 
well it depends on physics and shit. like what angles are the down slope and the ramp up, and how long the ramp up is. and how much snow you will have. but if its anything like mine (6ft tall) you will get a good amount of speed.
 
well what is the angle of teh ramp that has allot to do with it also. i have a 8ft tall ramps at a 45 degree angle and i get enought speed for prob a 2-3 ft tall 20 ft long flat rail at most maybe a little bit more. You can do bigger rails if they slope down.
 
weel, its gunna be made of wood, and it will probly be at like a 50 degree angle, and i need to know how much air u will get off a jump, not a rail length
 
when i run down mine you go pretty far. like not running fast or anything like just goin down then coasting and you go like 30 ft. and wit snow thats a good amount. im guessing if you make a jump thats 2 ft. tall you can gap 5ft. i dono. thats just a wild guess. ask a physics teacher at a school.
 
if you have a 6 foot drop in to a jump, its gonna be a pretty tiny jump. think about how long the inrun is for a normal jump at a resort, it's alot more than six feet vertical.
 
I've got a 10 foot ramp at some angle and it gives you alot of speed. almost too much for my 10ft PVC box.
 
the physics... forget mechanics just use energy, it depends on height of the ramp

mgh=mv^2/2

sqrt(2gh)=v
 
you should get the same speed no matter the ramp angle but you dont becuse of the friction of the snow, i forget the formula to figure it out, but it should give you nough speed if you build the trannies right to get you on a hand rail no prob
 
yah you'd go 12.8 mph, but then you'd have to factor in the energy lost due to friction, work=(friction force)(distance), but if your skis are waxed and its snow covered the friction is minimal hopefully
 
and if you really wanted to know, then it would be something along the lines of

m=mass

W=work due to friction

u=coefficient of friction between the snow and your skis which i do not know

mgh=PE

PE-W=(1/2)mv^2

mgh-umg=(1/2)mv^2

mg(h-u)=(1/2)mv^2

g(h-u)=(1/2)v^2

sqrt(2[g(h-u)])=v
 
wait i messed that up i forgot the length of the board, who cares anyway, if you want to be sure of the speed then make a huge ramp
 
they should build a little guinnee pig in there to make the test run... or a ball at the least
 
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