ts not hard to calculate... y=y + vt -1/2gt^2, distance doesnt matter at all, its how high in the air u go that determines airtime...
so without considering air resistance/ rotational effects,
if the lip of the jump is 3 meters above your landing, and angled at 45 degrees, goin off the lip at 10 m/s, or aprroximately 23 mph
i calculated time in the air to be 1.8 seconds, and u travel horizontally 12.7 m, or about 40 feet
and on this same jump youd go 2.55 m, or about 8.5 feet above the lip of the jump
but this is all neglecting drag and rotational effects
and i was really bored, but yeah, about 2 seconds