How do u find the hypotenuse of a triangle?

i havn't taken math since junior year but i think that its a^2 + b^2 = c^2 but it only works on right triangle or you gotta start using sine and cosine and such
 
or you can do it the fun way and use sin/cos/tan if they give you the inside angles of the triangle.
 
the only reason i pssed any of my tests was because of SOHCAHTOA i still dont know them without that
 
length of one leg squared (or if your so stupid you don't know what squared is just multiply that number by itself) then do that with the other leg of your triangle and you've got it!
 
or you can do the pythagorean theorem, but thankfully (i guess) i dont remember it anymore. i just remember it being a ppain in the ass.
 
you're in 9th grade geometry and you're learning the Pythagrian Theorem? lucky bastard. we did thats stuff in 6th grade.
 
SOH = Sine, opposite over hypotenuse

CAH = Cosine, adjacent over hypotenuse

TOA = Tangent, opposite over adjacent

SOHCAHTOA
 
its either a^2+b^2=c^2

OR

SOH CAH TOA

OR

side a/sinA=side b/sinB=side c/sinC (sine rule)

just shove the values in and then rearrange to make the unknown the subject
 
SOH= Sin - Opposite over Hypotnuese

CAH= Cosine - Adjacent over Hypotneuse

TOA= Tangent - Opposite over Adjacent
 
SOH= Sin - Opposite over Hypotnuese

CAH= Cosine - Adjacent over Hypotneuse

TOA= Tangent - Opposite over Adjacent
 
...with diagrams and the cosine rule!

sine_cosine_rules.gif
 
Sin(theta) = opposite/adjacent

Cos(theta) = adjacent/hypotenuse

Tan(theta) = opposite/adjacent

a^2 + b^2 = c^2

I figured since its been explained about 30 times I'd do it again.
 
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