Skibumsmith
Active member
((x^2y)^(1/3))((xy^2)^(2/3))
big ++++k if you can help
big ++++k if you can help
How do I do this?
- Thread starter Skibumsmith
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Skibumsmith
Active member
bump
Leo.
Member
((x^2y)^(1/3))((xy^2)^(2/3))
((x^2/3y^1/3)(x^2/3y^4/3)
x^4/3y^5/3
and then to express those wierd exponents, you make the numerator the exponent and and then take root of the bottom number.
so it would be cube root of x to the fourth, cube root of y to the fifth.
so actually the cube root of x to the fourth y to the fifth. all under one radical
((x^2/3y^1/3)(x^2/3y^4/3)
x^4/3y^5/3
and then to express those wierd exponents, you make the numerator the exponent and and then take root of the bottom number.
so it would be cube root of x to the fourth, cube root of y to the fifth.
so actually the cube root of x to the fourth y to the fifth. all under one radical
Skibumsmith
Active member
YAY! I FIGURED IT OUT!
(x^(4/3))((y^(5/3)) I spent an hour on it. Was it really worth it in the end?
(x^(4/3))((y^(5/3)) I spent an hour on it. Was it really worth it in the end?