Extra credit homework help.

W

Wes-Side

Member
So I know there are some pretty smart people on here (and even more dumbasses). Anyways my math teacher recently assigned an extra credit problem I was looking to get some help from people on here. If you do understand how to do this problem, I am not just looking for an easy answer, I would like to understand the steps used to get to that answer.
Anyways here is the question.
There are four large groups of people, each with 1000 members. Any two of these groups have 100 members in common. Any three of these groups have 10 members in common. Ad there is one person in all four groups. all together how many people are in these four groups
 
There's four groups with 1000 members each. How many people are there all together? Well unless I'm missing some major detail here it seems like the answer is 4000 people.
 
There ARE 4000 members but what you have to remember is that since people are in multiple groups it is not possible that the answer is 4000 people.
 
if he wanted to know that there was 234 people in common, he would have to be more specific. it is most likely asking for the total of all the people combined being 4000, trying to confuse you ahah
 
Actually nevermind, I probably mis-understood the question. Don't listen to me, I'm too tired for math.
 
haha lol. Don't be so harsh on them. I wish it was that easy. To everybody who thinks the answer is in the wording let me assure, it is a serious math problem.
 
Yeah, but the 4 groups can have interchangeable people. I dunno, too hard to explain, but i think i got it right. Im pretty good at math and logic and shit or whatever this is.
 
Could you work that out? Just to make sure everything is kosher before I go and try to explain the answer to my teacher.
 
its easier with a picture but ill try. So four groups, 2 have 100 in common, 3 have 10 in common, and 4 have 1 in common. So lets go backwards. subtract everything from 4000. 4 people(the four groups with these in common), 26(3 groups X 10 people = 30 - 4 because we already counted them), then 174(because 200 - 27) and that should equal 3797 if i did the math right, i always make stupid mistakes. lemmy do it again,

NOOO WAIT ITS 3796. THERE. Correct if wrong
 
I think you are right as when I first started this problem I took almost an identical course to figuring it out but for some reason I had a nagging doubt in the back of my mind that i had to be wrong somehow. Could everyone else now just look at the logic behind this and see if we are missing anything?
 
So 4000 people and ther 1 in common for all.

4000- ( 4+30+200) = your anser i dont have a calculator

So the 4 is beacause ther is one guy in all four groups the 30 beacause 10x3
And the 200 is the 100 common people x 2
 
Its a trick question, the person didnt specify if the common people are also common in the 10 people in 3 groups and the 100 people in 2 groups.
 
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