Chemistry!!!! sucks!!!!!!!

Tinga

Active member
since the freezing point of a solution depends on the relative number of particles, what would you calculate to be the freezing point of 0.1m solutions in water of a) NaCl b) BaCl2? assume that these salts are 100% ionized in solution.( compare your answers with the actually respective freezing points: -0.348 and -0.470 C. the difference is due to the decreased activity of the ions. because of the attractive forces between the positive and negatively charged ions, they do not move completely independently of one another.)
 
delta t = i * k * m

delta t: depression of freezing point

i: simply put-number of particles. For NaCl it would be 2, for BaCl2 it would be 3.

k: constant, in water it's 1.86

m: molarity
 
this is why i will never take anything over my required chem 1 class...fucking hate it. i would probably have a D in there if it wasn't for lab grades. this shit you are doing is crazy though.
 
no, it isn't.

if you were using molality, the equation would be delta t = k * molality. instead of molality, the equation I gave uses i (vant hoff factor, basically the number of moles in solution per 1 mole solute added) times molarity.
 
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