Any one know...

[Hansel.]

how to factor quadratic binomials?
9ysq.-49

 

[Mac.]

pretty simple since 9 and 49 are perfect square roots.

(3y-7)(3y+7)

 

[cab509]

really???

9y^2 - 49

(3y-7)(3y+7)

those are the easiest and things to factor, but there is your answer.

 

[BennyV]

Nah, again, its pretty simple. It all comes down to E=Mc^2