Algebra help

Scolson

Active member
This stuff is probably really easy but it's from the beginning of the year and i have no idea.

1)3-2i/4+3i

2)I thought i could solve this system by substituting but i fucked that up.

(3x-2y=7

(x+4y=7

and this one) f(x)= 3x^2 -1

 
damn i pressed repply accidentally

this one) f(x)= 3x^2 -1 g(x)=2/x

f (little circle thingy here) g(4) is what i need
 
2)I thought i could solve this system by substituting but i fucked that up.

3x-2y=7

x+4y=7

3(7-4y)-2y=7

21-12y-2y=7

-12y-2y=-14

y=(-14)/(-14)

y=1

x=3
 
yeah that's the symbol. i have no idea if you're right but you obviously know more than me i'll take your word for it
 
this is correct, the answer should be....

((3-2i)/(4+3i))((4-3i/4-3i)=(12-9i-8i-6i^2)/(16+9i^2) i think, i did that mostly in my head, could be off
 
haha idk why but i cant understand math on the computer. with like /=division and shit. and im actually smart too, oh well.
 
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