Scolson Active member Jun 7, 2007 #1 This stuff is probably really easy but it's from the beginning of the year and i have no idea. 1)3-2i/4+3i 2)I thought i could solve this system by substituting but i fucked that up. (3x-2y=7 (x+4y=7 and this one) f(x)= 3x^2 -1
This stuff is probably really easy but it's from the beginning of the year and i have no idea. 1)3-2i/4+3i 2)I thought i could solve this system by substituting but i fucked that up. (3x-2y=7 (x+4y=7 and this one) f(x)= 3x^2 -1
Scolson Active member Jun 7, 2007 #2 damn i pressed repply accidentally this one) f(x)= 3x^2 -1 g(x)=2/x f (little circle thingy here) g(4) is what i need
damn i pressed repply accidentally this one) f(x)= 3x^2 -1 g(x)=2/x f (little circle thingy here) g(4) is what i need
ThaLetterM. Active member Jun 7, 2007 #4 i just took my algebra II exam today and i gotta tell you...i have no idea about anything. sorry man.
i just took my algebra II exam today and i gotta tell you...i have no idea about anything. sorry man.
Scolson Active member Jun 7, 2007 #7 yeah, Im supposed to show work so i'll write down some garbage. k thx
Scolson Active member Jun 7, 2007 #9 #1 is multiple choice 6/25-7/25i 6/25-17/25i 18/5-17/5i 18/25-17/25i
M mauii Active member Jun 7, 2007 #10 2)I thought i could solve this system by substituting but i fucked that up. 3x-2y=7 x+4y=7 3(7-4y)-2y=7 21-12y-2y=7 -12y-2y=-14 y=(-14)/(-14) y=1 x=3
2)I thought i could solve this system by substituting but i fucked that up. 3x-2y=7 x+4y=7 3(7-4y)-2y=7 21-12y-2y=7 -12y-2y=-14 y=(-14)/(-14) y=1 x=3
Scolson Active member Jun 7, 2007 #12 yeah that's what I did but I messed up and ended up with some crazy assed decimal. im dum
Scolson Active member Jun 7, 2007 #14 yeah that's the symbol. i have no idea if you're right but you obviously know more than me i'll take your word for it
yeah that's the symbol. i have no idea if you're right but you obviously know more than me i'll take your word for it
G Gavajabra2 Active member Jun 7, 2007 #15 If its 3-2i/4+3i then just multiply it by the recipricle so: 3-2i/4+3i times 4-3i/4-3i
M mauii Active member Jun 7, 2007 #16 If thats what he meant, then thats right, except you forgot the -1 after 3/4
M+M Active member Jun 8, 2007 #22 this is correct, the answer should be.... ((3-2i)/(4+3i))((4-3i/4-3i)=(12-9i-8i-6i^2)/(16+9i^2) i think, i did that mostly in my head, could be off
this is correct, the answer should be.... ((3-2i)/(4+3i))((4-3i/4-3i)=(12-9i-8i-6i^2)/(16+9i^2) i think, i did that mostly in my head, could be off
comeatmebro Active member Jun 8, 2007 #23 haha idk why but i cant understand math on the computer. with like /=division and shit. and im actually smart too, oh well.
haha idk why but i cant understand math on the computer. with like /=division and shit. and im actually smart too, oh well.
Scolson Active member Jun 8, 2007 #25 it's ok guys its over. I was completely blown away about the score ig ot on the test
S Skierguy1234 Active member Jun 8, 2007 #26 1)3-2i/4+3i mult everything by 4 12-2i+12i combine like terms 12+10i i think that right, but im not sure.
1)3-2i/4+3i mult everything by 4 12-2i+12i combine like terms 12+10i i think that right, but im not sure.
R Rooddss Active member Jun 8, 2007 #27 very easy stuff, f(x) = y and then ill do the rest later haha