PreCal Halp. K+ for answers

[yeahno]

basically, if you have the cube root of X, and i want to shift it left like, 10 units, is the equation

X^((1/3)+10)?

because i enter that on my calculator and it like completely wrecks it

so ns, its a cube root, and i want to shift it left by 10 units, whats the equation?

 

[Caspaaa]

it should be x^(1/3+10)

the plus ten in the exponent

x^(1/3)+10 would shift it up 10

 

[Ziolent]

^ you guys both put in the same thing. OP just put parenthesis around the 1/3, but you don't need them. Order of operations bro.

You guys should get the same graph...

 

[NataliePortman]

f(x)=(^3√x)+10

maybe?? i havent taken precal in years

 

[Caspaaa]

i put it in my calculator and it didn't work

however it should be f(x)=(cuberoot) of (x+10)

^plug that in and it works

 

[Caspaaa]

easier to understand this way

f(x)=3√(x+10)

 

[.spaghetticat.]

( x Y x )={212 83920

 

[NataliePortman]

I checked wolfram and x^1/3 is a completely diff graph than x^1/3+10 because thats like saying x^4/3

 

[blatt]

If you want to shift it left, the +10 goes with the X rather than the exponent.

y=(x+10)^(1/3)

 

[NataliePortman]

steal my answer bro, wanna fight?!?!?!?!? lol

 

[Ziolent]

This is correct.

 

[yeahno]

Much thanks to all!!!!!!