Math problem +K for answer

tribefan226

Active member
Suppose that a hawk, whose initial position is
fitzgerald.148-prob1image1.png


on the
fitzgerald.148-prob1image2.png
-axis, spots a pigeon at
fitzgerald.148-prob1image3.png
on the
fitzgerald.148-prob1image4.png
-axis.

Suppose that the pigeon flies at a constant speed of 50 ft/sec in

the direction of the
fitzgerald.148-prob1image5.png
-axis (oblivious to the hawk), while

the hawk flies at a constant speed of 60 ft/sec, always in the

direction of the pigeon.

The problem is to find an equation for the flight path of the

hawk (the curve of pursuit) and to find the time and place where

the hawk will catch the pigeon. Assume that in this problem all

distances are measured in feet and all times measured in seconds.

Leave out all dimensions from your answers.

Consider the diagram above (click on it for a better view)

which represents the situation at an arbitrary

time
fitzgerald.148-prob1image6.png
during the pursuit. The points
fitzgerald.148-prob1image7.png
and
fitzgerald.148-prob1image8.png
represent

the positions of the hawk and pigeon respectively at that time instant

fitzgerald.148-prob1image9.png
, with
fitzgerald.148-prob1image10.png
representing the flight path of the hawk.

The pigeon's position
fitzgerald.148-prob1image11.png
is given by the following function of time

fitzgerald.148-prob1image12.png
=

The fact that the hawk is always headed in the direction of the pigeon

means that the line
fitzgerald.148-prob1image13.png
is tangent to the pursuit curve
fitzgerald.148-prob1image14.png
.

This tells us that
fitzgerald.148-prob1image15.png
where

fitzgerald.148-prob1image16.png
=?????

(Your answer must involve the three variables
fitzgerald.148-prob1image17.png
,
fitzgerald.148-prob1image18.png
, and
fitzgerald.148-prob1image19.png
)

 
seriously this is pretty basic if you break it down..just plug in the numbers with E=mc2, and dont forget to carry the one near the end of the equation.
 
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