Koalataze Member Mar 5, 2013 #1 so heres the problem. i have no clue what im doing. we are supposed to be using derivatives and such. boyle's law states that pv=c, where p is pressure, v is volume, and c is a constant. find a formula for the rate of change of p with respect to v.
so heres the problem. i have no clue what im doing. we are supposed to be using derivatives and such. boyle's law states that pv=c, where p is pressure, v is volume, and c is a constant. find a formula for the rate of change of p with respect to v.
O O-A_s Member Mar 5, 2013 #2 http://www.wolframalpha.com/input/?i=derive+y%3Dc%2Fx I suppose this is what you are looking for? I just changed p to y and v to x. p'(v)= - c/v^2
http://www.wolframalpha.com/input/?i=derive+y%3Dc%2Fx I suppose this is what you are looking for? I just changed p to y and v to x. p'(v)= - c/v^2
HamFaceGirl Active member Mar 5, 2013 #4 If youre tring to find the derivative for v=c/p then its ((c'p)-(cp'))/p^2 but then you need all those values too, so that's up to you. It would help if you were a little more descriptive
If youre tring to find the derivative for v=c/p then its ((c'p)-(cp'))/p^2 but then you need all those values too, so that's up to you. It would help if you were a little more descriptive