hobbes Member Apr 16, 2007 #1 If "Log a B = c^4" and "Log b A = 5/c^3" prove that c= 1/5 lower case letters are suppsoed to be subscripts and the "^" sign is exponet and the "/" is a fraction sign. Any help would be great.
If "Log a B = c^4" and "Log b A = 5/c^3" prove that c= 1/5 lower case letters are suppsoed to be subscripts and the "^" sign is exponet and the "/" is a fraction sign. Any help would be great.
hobbes Member Apr 16, 2007 #4 it's definitley Advanced Math 12, which is a step up from grade 12 adcademic math but I am taking it in grade 11 to take pre- cal next year.
it's definitley Advanced Math 12, which is a step up from grade 12 adcademic math but I am taking it in grade 11 to take pre- cal next year.
U user098123 Active member Apr 16, 2007 #5 If "Log a B = c^4" and "Log b A = 5/c^3" prove that c= 1/5 Use antilogs. If Log a B = C^4 then a^(C^4) = B, and for Log b A = 5/(C^3), b^(5/(C^3)) = A, solve from there.
If "Log a B = c^4" and "Log b A = 5/c^3" prove that c= 1/5 Use antilogs. If Log a B = C^4 then a^(C^4) = B, and for Log b A = 5/(C^3), b^(5/(C^3)) = A, solve from there.
mmmmm...Pie Member Apr 16, 2007 #6 Log a B = C^4 --> B = A * C^4 Log b A = 5/C^3 --> A = B * 5/C^3 Sub in "B*5/C^3" for A --> B = B * 5/C^3 * C^4 C's cancel --> B = B * 5 * C Divide both sides by 5B (B's cancel) --> 1/5 = C
Log a B = C^4 --> B = A * C^4 Log b A = 5/C^3 --> A = B * 5/C^3 Sub in "B*5/C^3" for A --> B = B * 5/C^3 * C^4 C's cancel --> B = B * 5 * C Divide both sides by 5B (B's cancel) --> 1/5 = C
squeakywaffle Active member Apr 16, 2007 #7 Since log a b = c^4, a^(c^4) = b. So, a = b^(1/c^4). So, bringing the other equation into the mix, we get: b^(1/c^4) = b^(5/c^3) So, 1/c^4 = 5/c^3 and 1/5 = c^4/c^3. Cancel on the right side and you get: 1/5 = c. thankyouverymuch
Since log a b = c^4, a^(c^4) = b. So, a = b^(1/c^4). So, bringing the other equation into the mix, we get: b^(1/c^4) = b^(5/c^3) So, 1/c^4 = 5/c^3 and 1/5 = c^4/c^3. Cancel on the right side and you get: 1/5 = c. thankyouverymuch