A mathematical riddle...

ShoulderSurfer

ShoulderSurfer

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Three guys check into a whore-house for the night and the pimp tells them it’s $30 for the hooker, payable in advance. So, they each pay the pimp $10 and go to the hooker’s room. A few minutes later, the clerk realizes he has made an error and overcharged the trio by $5. He as...ks the bellhop to return $5 to the 3 guys who had just checked in. The bellhop sees this as an opportunity to make $2 as he reasons that the three guys would have a tough time dividing $5 evenly among them; so he decides to tell them that the pimp made a mistake of only $3, giving a dollar back to each of the friends. He pockets the leftover $2 and goes home for the day! Now, each of the three guys gets a dollar back, thus they each paid $9 for the room which is a total of $27 for the night. We know the bellhop pocketed $2 and adding that to the $27, you get $29, not $30 which was originally spent. Where did the other dollar go????
 
basically the question is, if they each get one dollar back, then they each payed 9 dollars, and since 9 x 3= 27, and the bellhop only kept 2, there is only a grand total of 29 bucks, what happened to the other dollar.
 
Pimp: 25

Bell boy: 2

Guys: 3

Total: 30

If you go by what each guy paid you get 9X3 which is 27. 25 of that is in the pimps hand and 2 of that is in the bell boys hand. You can't add the bell boys money to the 27 because he already has 2 dollars from the original sum.

So the original 30 goes as such. 25 to the pimp, 2 to bellboy and 3 to dudes who are going to have an orgy, the bad kind of orgy.
 
1. guys give the pimp $30

2. pimp tells bellhop to give them $5 back

3. bellhop pockets $2 and gives the dudes $3.

4. = $30

5. ???

6. profit

How is this a riddle?
 
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