8th Grade math is kicking my ass.

Albrecht.

Albrecht.

Active member
someone help me with this embarassing problem.

i pitched for a blunt sesh about an hour ago and came home to do my english project. im making a pyramid out of foam posterboard cutouts. base is a 16x16in square. i want the triangles to be equilateral with legs of 16in. What will the height of my triangles be. My blazed ass is all twisted up in pythagarus and square roots. did the equation about six times and each time i came up with 17.8in. i know thats not right its impossible. help me out ns.
 
yah but its equilateral. i thought if you used a line from the midpoint of a side to the opposite vertex you could use pythagarous on one of the newly formed right triangles to find the height.
 
well, if you want to have a equilateral triangles with sides of 16, that's fine.. the height of your triangles will be about 13.356,  or the square root of 192.  you said you want the legs to equal 16, but hopefully by legs you mean sides, because legs are only found in right triangles and an equilateral triangle cannot be a right triangle. i hope that makes sense. i think the number you're looking for is the root of 192. 
 
a^2 + b^2 = c^2 (pathegoren (sp?) theorem)

8^2 + h^2 = 16^2 (think about the triangle your using. another shortcut is a 30-60-90 triangle, where the hypotenuse is double the length of the shortest leg and the longer leg is the square root of 3 times the shorter leg, that should give help you alot)

h = 8 times root 3 which is about 13.9

dude your 17 though? genius man
 
if u draw a line that bisects the base leg of the triangle to make it 8 in use pythagorean therom

8^2 + B^2 = 16^2

16^2 - 8^2 = B^2
 
ah fuck.... 16^2 + 8^2 = c^2 is what i was doing. this is definatly going in the you know your stoned when ... thread in 420.
 
a^2 + b^2 = c^2 c is the hypoteneuse or longest side which is 16 in in your case. a and b are interchangeable so one is half of 16(8) because you dropped a perpendicular from a vertice to one side (cutting it in half)so now you have

8^2 +b^2 = 16^2 or

64 + b^2 = 256 now simple algebra

b^2 = 256 - 64

so b^2 = 192

so b = 13.8

also remember it is an equilateral triangle so all sides are the same length and also all the angles are the same and since there are 360 degrees in a traingle each angle is 120 degrees
 
I'm too lazy to look at your numbers, but I dont see how that is so challenging. are you using a calculator??
 
imagine if you were on are you smarter than a 5th grader, you'd be fucked, that really has nothing to do with 8th grade math but just imagine it
 
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